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Recent questions tagged nielit2019feb-scientistc

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42
NIELIT 2019 Feb Scientist C - Section D: 15
The simplified form of $\left[ \left ( \left( \dfrac{a+1}{a-1}\right)^2+3 \right)\div \left( \left( \dfrac{a-1}{a+1}\right)^2+3\right) \right] \div \left [\left( \dfrac{a^{3}+1}{a^{3}-1}\right)-\dfrac{2a}{a-1} \right]$ is: $a-1$ $1-a$ $-1$ $1$
The simplified form of $\left[ \left ( \left( \dfrac{a+1}{a-1}\right)^2+3 \right)\div \left( \left( \dfrac{a-1}{a+1}\right)^2+3\right) \right] \div \left [\left( \dfrac{a...
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NIELIT 2019 Feb Scientist C - Section D: 12
A conical tent is to accommodate $10$ persons. Each person must have $6m^{2}$ space to sit and $30m^{3}$ of air to breath. What will be height of cone? $37.5$ m $150$ m $75$ m $15$ m
A conical tent is to accommodate $10$ persons. Each person must have $6m^{2}$ space to sit and $30m^{3}$ of air to breath. What will be height of cone?$37.5$ m$150$ m$75$...
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NIELIT 2019 Feb Scientist C - Section D: 16
If $cosec\theta-\sin\theta=1$ and $\sec\theta-\cos\theta=m$, then $l^{2}m^{2}(l^{2}+m^{2}+3)$ equals to: $1$ $2$ $2 \sin\theta$ $\sin\theta \cos\theta$
If $cosec\theta-\sin\theta=1$ and $\sec\theta-\cos\theta=m$, then $l^{2}m^{2}(l^{2}+m^{2}+3)$ equals to:$1$$2$$2 \sin\theta$$\sin\theta \cos\theta$
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NIELIT 2019 Feb Scientist C - Section D: 19
If $x=\dfrac{\sqrt{10}+\sqrt{2}}{2}, \: \: y=\dfrac{\sqrt{10}-\sqrt{2}}{2}$ then the value of $\log _{2}(x^{2}+xy+y^{2})$ is: $0$ $1$ $2$ $3$
If $x=\dfrac{\sqrt{10}+\sqrt{2}}{2}, \: \: y=\dfrac{\sqrt{10}-\sqrt{2}}{2}$ then the value of $\log _{2}(x^{2}+xy+y^{2})$ is:$0$$1$$2$$3$
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50
NIELIT 2019 Feb Scientist C - Section D: 23
Rs.$6500$ were divided among a certain number of persons. If there had been $15$ more persons, each would have got $Rs.30$ less. Find the original number of persons. $50$ $60$ $45$ $55$
Rs.$6500$ were divided among a certain number of persons. If there had been $15$ more persons, each would have got $Rs.30$ less. Find the original number of persons.$50$$...
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NIELIT 2019 Feb Scientist C - Section D: 21
Find the number of numbers between $300$ to $400$ (both included) that are not divisible by $2,3,4$ and $5$ $50$ $33$ $26$ $17$
Find the number of numbers between $300$ to $400$ (both included) that are not divisible by $2,3,4$ and $5$$50$$33$$26$$17$
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NIELIT 2019 Feb Scientist C - Section D: 25
If $x+y+z=2, \:\: xy+yz+zx=-1$ then the value of $x^{3}+y^{3}+z^{3}$ is: $20$ $16$ $8$ $0$
If $x+y+z=2, \:\: xy+yz+zx=-1$ then the value of $x^{3}+y^{3}+z^{3}$ is:$20$$16$$8$$0$
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60
NIELIT 2019 Feb Scientist C - Section D: 29
If $(-4,0),(1,-1)$ are two vertices of a triangle whose area is $4$ Sq units then its third vertex lies on: $y=x$ $5x+y+12=0$ $x+5y-4=0$ $x-5y+4=0$
If $(-4,0),(1,-1)$ are two vertices of a triangle whose area is $4$ Sq units then its third vertex lies on:$y=x$$5x+y+12=0$$x+5y-4=0$$x-5y+4=0$
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NIELIT 2019 Feb Scientist C - Section C: 3
The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are: $(x-2y-4)(x-2y+2)$ $(x-y+2)(x-4y-4)$ $(x+2y-4)(x+2y+2)$ None of these
The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are:$(x-2y-4)(x-2y+2)$$(x-y+2)(x-4y-4)$$(x+2y-4)(x+2y+2)$None of these
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NIELIT 2019 Feb Scientist C - Section C: 1
If $\log _{e}x+\log _{e}(1+x)=0,$ then: $x^{2}+x-1=0$ $x^{2}+x+1=0$ $x^{2}+x-e=0$ $x^{2}+x+e=0$
If $\log _{e}x+\log _{e}(1+x)=0,$ then:$x^{2}+x-1=0$$x^{2}+x+1=0$$x^{2}+x-e=0$$x^{2}+x+e=0$
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63
NIELIT 2019 Feb Scientist C - Section C: 2
If the ratio of the areas of two squares is $9:1$, the ratios of their perimeters is: $9:1$ $3:1$ $3:4$ $1:3$
If the ratio of the areas of two squares is $9:1$, the ratios of their perimeters is:$9:1$$3:1$$3:4$$1:3$
2 votes
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NIELIT 2019 Feb Scientist C - Section C: 6
In a class consisting of $100$ students, $20$ know English and $20$ do not know Hindi and $10$ know neither English nor Hindi. The number of students knowing both Hindi and English is: $5$ $10$ $15$ $20$
In a class consisting of $100$ students, $20$ know English and $20$ do not know Hindi and $10$ know neither English nor Hindi. The number of students knowing both Hindi a...
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66
NIELIT 2019 Feb Scientist C - Section C: 5
By which one of the following should we multiply $152207$ so that the product is $11111111$? $53$ $63$ $73$ $83$
By which one of the following should we multiply $152207$ so that the product is $11111111$?$53$$63$$73$$83$
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NIELIT 2019 Feb Scientist C - Section C: 11
For a sphere of radius $10$ cm, the numerical value of the surface area is how many percent of the numerical value of its volume? $26.5\%$ $24\%$ $30\%$ $45\%$
For a sphere of radius $10$ cm, the numerical value of the surface area is how many percent of the numerical value of its volume?$26.5\%$$24\%$$30\%$$45\%$
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NIELIT 2019 Feb Scientist C - Section C: 10
A sum of money amounts to $₹6,690$ after $3$ years and to $₹10,035$ after $6$ years on compound interest. The sum is: $₹4,400$ $₹4,460$ $₹4,520$ $₹4,445$
A sum of money amounts to $₹6,690$ after $3$ years and to $₹10,035$ after $6$ years on compound interest. The sum is:$₹4,400$$₹4,460$$₹4,520$$₹4,445$
1 votes
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NIELIT 2019 Feb Scientist C - Section C: 14
Kamla got married $6$ years ago. Today her age is $1\dfrac{1}{4}$ times of her age at the time of marriage. Her son’s age is $\dfrac{1}{10}$ times of her age. Her son’s age is : $2$ years $3$ years $4$ years $5$ years
Kamla got married $6$ years ago. Today her age is $1\dfrac{1}{4}$ times of her age at the time of marriage. Her son’s age is $\dfrac{1}{10}$ times of her age. Her son�...
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75
NIELIT 2019 Feb Scientist C - Section C: 15
Tarun bought a T.V with $20\%$ discount on the labelled price. If he had bought it with $25\%$ discount, he would have saved $₹500$. At what price did he buy the T.V.? $₹8,000$ $₹10,000$ $₹12,000$ $₹16,000$
Tarun bought a T.V with $20\%$ discount on the labelled price. If he had bought it with $25\%$ discount, he would have saved $₹500$. At what price did he buy the T.V.?$...
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NIELIT 2019 Feb Scientist C - Section C: 12
About the number of pairs which have $16$ as their H.C.F. and $136$ as their L.C.M., we can definitely say that: Only one such pair exists Only two such pairs exist Many such pairs exist No such pair exists
About the number of pairs which have $16$ as their H.C.F. and $136$ as their L.C.M., we can definitely say that:Only one such pair existsOnly two such pairs existMany suc...
1 votes
2 answers
78
NIELIT 2019 Feb Scientist C - Section C: 19
If $a^{x}=b, b^{y}=c$ and $c^{z}=a$, then $xyz$ equals: $abc$ $\dfrac{1}{abc}$ $1$ None
If $a^{x}=b, b^{y}=c$ and $c^{z}=a$, then $xyz$ equals:$abc$$\dfrac{1}{abc}$$1$None
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NIELIT 2019 Feb Scientist C - Section C: 18
On dividing $50$ into two parts such that the sum of their reciprocals is $\dfrac{1}{12}$, we get the parts as: $20,30$ $24,26$ $28,22$ $36,14$
On dividing $50$ into two parts such that the sum of their reciprocals is $\dfrac{1}{12}$, we get the parts as:$20,30$$24,26$$28,22$$36,14$
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