0 0 votes The sum of the squares of the fifth and the eleventh term of an AP is $3$ and the product of the second and fourteenth term is equal to $x$. Find the product of the first and fifteenth term of an AP. $\dfrac{(58x-39)}{45} \\$ $\dfrac{(98x-39)}{72} \\$ $\dfrac{(116x-39)}{90} \\$ $\dfrac{(98x-39)}{90}$ Quantitative Aptitude nielit2019feb-scientistc quantitative-aptitude sequences&series + – Lakshman Bhaiya 12.2k points 1.4k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.