NIELIT 2019 Feb Scientist C - Section C: 17

Question

A man invests an amount of $\text₹15,860$ in the names of his three sons $A,B$ and $C$ in such a way that they get the same interest after $2,3$ and $4$ years respectively. If the rate of simple interest is $5\%$, then the ratio of the amounts invested among $A,B$ and $C$ will be

• A. $10:15:20$
• B. $110:115:120$
• C. $\dfrac{1}{10} : \dfrac{1}{15}:\dfrac{1}{20}$
• D. $\dfrac{1}{110}:\frac{1}{115}:\frac{1}{120}$

Answer 1

Answer is C

Let the amount the man invested from the sum of Rs.15860 in the name of 3 sons be x, y and z. As the Simple Interest received is same,

$\frac{x*2*5}{100}=\frac{x*3*5}{100}=\frac{x*4*5}{100}$ = k, so 

$x:y:z=\frac{100k}{10}:\frac{100k}{15}:\frac{100k}{20}$

Divide by 100k, we will get

$x:y:z=\frac{1}{10}:\frac{1}{15}:\frac{1}{20}$