$\frac{1}{3} \log_3 M + 3 \log_3 N=1 + \log_{0.008} 5$
$\log_3 M^{\frac{1}{3}} + \log_3 N^{3}=1 + \log_{0.008} 5$
$\log_3 M^{\frac{1}{3}} N^{3}=1 + \log_{0.008} 5$
$\log_3 M^{\frac{1}{3}} N^{3}=1 + \frac{\log 5 }{\log 0.008}$
$\log_3 M^{\frac{1}{3}} N^{3}=1 + \frac{\log \frac{10}{2} }{\log \frac{8}{1000}}$
$\log_3 M^{\frac{1}{3}} N^{3}=1 + \frac{\log10 - \log 2 }{\log 8 - \log 1000}$
$\log_3 M^{\frac{1}{3}} N^{3}=1 + \frac{\log10 - \log 2 }{3(\log 2 - \log 10)}$
$\log_3 M^{\frac{1}{3}} N^{3}=1-\frac{1}{3}$
$\log_3 M^{\frac{1}{3}} N^{3}=\frac{2}{3}$
$M^{\frac{1}{3}} N^{3}=3^{\frac{2}{3}}$
$M* N^{9}=9$
$N^{9}=\frac{9}{M}$
Hence,Option(B)$N^{9}=\frac{9}{M}$ is the correct choice.