Register

CAT 2003 | Question: 1-106

• edited by
2,100 views

Please log in or register to answer this question.

Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →

Related questions

0 votes
0 votes
0 answers
1
go_editor asked Feb 10, 2016
635 views
CAT 2003 | Question: 1-140
if $\log_3\left(2^x - 5\right), \: \log_3\left(2^x - \frac{7}{2}\right)$ are in arithmetic progression, then the value of $x$ is equal to $5$ $4$ $2$ $3$
if $\log_3\left(2^x - 5\right), \: \log_3\left(2^x - \frac{7}{2}\right)$ are in arithmetic progression, then the value of $x$ is equal to$5$$4$$2$$3$
1 votes
1 votes
1 answer
2
go_editor asked May 5, 2016
631 views
CAT 2003 | Question: 2-96
What is the sum of '$n$' terms in the series: $\log m + \log \frac{m^2}{n} + \log \frac{m^3}{n^2} + \log \frac{m^4}{n^3} + \dots + \log \frac{m^n}{n^{n-1}}?$ $\log \left[\frac{n^{n-1}}{m^{(n+1)}} \right]^{\frac{n}{2}}$ ... $\log \left[\frac{m^{(n+1)}}{n^{(n-1)}} \right]^{\frac{n}{2}}$
What is the sum of '$n$' terms in the series: $\log m + \log \frac{m^2}{n} + \log \frac{m^3}{n^2} + \log \frac{m^4}{n^3} + \dots + \log \frac{m^n}{n^{n-1}}?$$\log \left[\...
1 votes
1 votes
1 answer
3
go_editor asked May 5, 2016
535 views
CAT 2003 | Question: 2-93
If $\log_{10} x - \log_{10} \sqrt{x} = 2 \log_x 10$ then a possible value of $x$ is given by $10$ $\frac{1}{100}$ $\frac{1}{1000}$ None of these
If $\log_{10} x - \log_{10} \sqrt{x} = 2 \log_x 10$ then a possible value of $x$ is given by$10$$\frac{1}{100}$$\frac{1}{1000}$None of these
0 votes
0 votes
1 answer
4
go_editor asked May 5, 2016
614 views
CAT 2003 | Question: 2-74
If $\frac{1}{3} \log_3 \text{M} + 3 \log_3 \text{N} =1 + \log_{0.008} 5$, then $\text{M}^9 = \frac{9}{\text{N}}$ $\text{N}^9 = \frac{9}{\text{M}}$ $\text{M}^3 = \frac{3}{\text{N}}$ $\text{N}^9 = \frac{3}{\text{M}}$
If $\frac{1}{3} \log_3 \text{M} + 3 \log_3 \text{N} =1 + \log_{0.008} 5$, then$\text{M}^9 = \frac{9}{\text{N}}$$\text{N}^9 = \frac{9}{\text{M}}$$\text{M}^3 = \frac{3}{\te...
Link Copied!