0 0 votes The factors of $(x^{2}+4y^{2}+4y-4xy-2x-8)$ are: $(x-2y-4)(x-2y+2)$ $(x-y+2)(x-4y-4)$ $(x+2y-4)(x+2y+2)$ None of these Quantitative Aptitude nielit2019feb-scientistc algebra + – Lakshman Bhaiya 12.2k points 2.0k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Multiply factors , you’ll get option A. Ref: https://www.toppr.com/en-in/ask/question/what-are-the-factors-of-x2-4y2-4y-4xy-2x/ Devwritt answered Nov 19, 2020 Devwritt 384 points comment Share Follow 0 reply Please log in or register to add a comment.