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Recent questions tagged straight-lines

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2 answers
1
NIELIT 2019 Feb Scientist D - Section D: 4
If $P$\left (x, y \right)$ is any point on the line joining the points $A$\left (a, 0 \right)$ and $B$\left(0, b \right)$ then the value of $bx+ay-ab$ is : $1$ $-1$ $0$ $2$
If $P$$\left (x, y \right)$ is any point on the line joining the points $A$$\left (a, 0 \right)$ and $B$$\left(0, b \right)$ then the value of $bx+ay-ab$ is :$1$$-1$$0$$2...
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1 answer
2
NIELIT 2019 Feb Scientist D - Section D: 29
The image of the point $\left (3, 8 \right)$ in the line $x+3y=7$ is : $\left (1, 4 \right)$ $\left (4, 1 \right)$ $\left (-1, -4 \right)$ $\left (-4, -1 \right)$
The image of the point $\left (3, 8 \right)$ in the line $x+3y=7$ is :$\left (1, 4 \right)$$\left (4, 1 \right)$$\left (-1, -4 \right)$$\left (-4, -1 \right)$
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2 answers
3
NIELIT 2019 Feb Scientist C - Section D: 3
The line $x+y=4$ divides the line joining $\text{(-1,1) & (5,7)}$ in the ratio $\lambda : 1$ then the value of $\lambda$ is: $2$ $3$ $\dfrac{1}{2}$ $1$
The line $x+y=4$ divides the line joining $\text{(-1,1) & (5,7)}$ in the ratio $\lambda : 1$ then the value of $\lambda$ is:$2$$3$$\dfrac{1}{2}$$1$
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1 answer
4
NIELIT 2019 Feb Scientist C - Section D: 10
Let $(x_{1},4),(-2,y_{1})$ lies on the line joining the points $(2,-1),(5,-3)$ then the point $P(x_{1},y_{1})$ lies on the line: $6(x+y)-25=0$ $2x+6y+1=0$ $2x+3y-6=0$ $6(x+y)+25=0$
Let $(x_{1},4),(-2,y_{1})$ lies on the line joining the points $(2,-1),(5,-3)$ then the point $P(x_{1},y_{1})$ lies on the line:$6(x+y)-25=0$$2x+6y+1=0$$2x+3y-6=0$$6(x+y...
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