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How many 3-digit numbers can be formed from the digits 2,3,5,6,7 and 9,which are divisible by 5 and none of the digits is repeated ?

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To be divisible by 5 the last digit must be 5 (0 is not given). So, we only have choice for remaining 2 digits and they can come from $\{2,3,6,7,9\}$ without repetition and order matters (215 and 125 are different). So, total number of such numbers $$= {}^5P_2 = 20.$$
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