suppose, the seed of any positive integer $n$ is defined as follows:
seed$(n) = n,$ if $n < 10$
$=$seed$(s(n)),$ otherwise
where $s(n)$ indicates the sum of digits $n.$ For example, seed$(7)=7,$ seed$(248) =$ seed$(2+4+8) =$ seed$(14) =$ seed$(1 + 4) =$ seed$(5) = 5$ etc. How many positive integers $n,$ such that $n <500,$ will have seed$(n) =9?$
- $39$
- $72$
- $81$
- $108$
- $55$