OPTION-->A
Since the order of seating matters ,we are going to choose permutations here.
Suppose ABCDE are 4 mens and one women respectively, ABCDE =! ABCED.
So coming to the question,4 men and 3 women together.
Consider 3 women as a single block and total no of persons =5.
For first position we have 5 choices ,next 4..3..2..1.
We can arrange in 5! ways.Since the block of women is jumbled across,the 3 women can be placed themselves along in 3! ways.
So the final answer will be 3!.5!=6*120=720.