3 3 votes Choose the best alternative If $\log_{7} \log_{5} (x+5x+x)=0$; find the value of $x$. 1 0 2 None of these Quantitative Aptitude cat1994 quantitative-aptitude logarithms + – Misbah Ghaya 8.8k points 3.5k views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply just_bhavana 1.5k points commented Oct 15, 2017 reply Follow flag some mistake in question ? 2 2 replyShare Lakshman Bhaiya 12.2k points commented Nov 14, 2017 reply Follow flag Most of the people not visited here why? 0 0 replyShare Please log in or register to add a comment.
0 0 votes Question should have been : If log7log5(x+5x+x)=0 , then find x . Solving accordingly, log7(7x)=50 => log7(7x)=1 => 7x=7 Hence x=1 Sayan Bose answered Nov 6, 2017 Sayan Bose 146 points comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes given, log7log5(x+5x+x) = 0 now, we know that 7^0 = 1 therefore, log5(x+5x+x) = 1 now, 5 = x + 5x + x 5 = 7x x = 5/7 therefore answer is D) let_me_var answered Jul 15, 2025 let_me_var 20 points comment Share Follow 0 reply Please log in or register to add a comment.