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3 3 votes

Choose the best alternative

If $\log_{7} \log_{5} (x+5x+x)=0$; find the value of $x$.

  1. 1
  2. 0
  3. 2
  4. None of these

2 Answers

0 0 votes

Question should have been : If log7log5(x+5x+x)=0 , then find x .

Solving accordingly, log7(7x)=50

=> log7(7x)=1 

=> 7x=7 Hence x=1 

0 0 votes
given,

log7log5(x+5x+x) = 0

now, we know that 7^0 = 1
therefore,

log5(x+5x+x) = 1
now,

5 = x + 5x + x

5 = 7x

x = 5/7

 

therefore answer is D)
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