0 0 votes Let $a_{n}$ be the $n^{\text {th }}$ term of a decreasing infinite geometric progression. If $a_{1}+a_{2}+a_{3}=52$ and $a_{1} a_{2}+a_{2} a_{3}+a_{3} a_{1}=624$, then the sum of this geometric progression is$57$$54$$60$$63$ Others cat2025-set2 + – Shubham Sharma 2 4.7k points 120 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.