0 0 votes The set of all real values of $x$ for which $(x^{2}-\mid x+9 \mid +x)>0$, is$(-\infty,-3) \cup(3, \infty)$$(-\infty,-9) \cup(3, \infty)$$(-9,-3) \cup(3, \infty)$$(-\infty,-9) \cup(9, \infty)$ Others cat2025-set2 + – Shubham Sharma 2 4.7k points 138 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.