1 1 vote In a rectangle $A B C D, A B=9 \mathrm{~cm}$ and $B C=6 \mathrm{~cm}$. $P$ and $Q$ are two points on $B C$ such that the areas of the figures $A B P, A P Q$, and $A Q C D$ are in geometric progression. If the area of the figure $A Q C D$ is four times the area of triangle $A B P$, then $B P: P Q: Q C$ is $1: 1: 2$ $1: 2: 1$ $1: 2: 4$ $2: 4: 1$ Quantitative Aptitude cat2023-set2 quantitative-aptitude geometry + – admin 5.3k points 1.4k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.