1 1 vote Any non-zero real numbers $\mathrm{x}$, $\mathrm{y}$ such that $y \neq 3$ and $\frac{x}{y}<\frac{x+3}{y-3}$, will satisfy the condition$\frac{x}{y}<\frac{y}{x}$If $y>10$, then $-x>y$If $x<0$, then $-x<y$If $y<0$, then $-x<y$ Quantitative Aptitude cat2023-set2 quantitative-aptitude fractions + – admin 5.3k points 1.0k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.