2 2 votes If $\sqrt{5 x+9}+\sqrt{5 x-9}=3(2+\sqrt{2})$, then $\sqrt{10 x+9}$ is equal to $3 \sqrt{7}$ $4 \sqrt{5}$ $3 \sqrt{31}$ $2 \sqrt{7}$ Quantitative Aptitude cat2023-set1 quantitative-aptitude algebra numerical-answer + – admin 5.3k points 1.8k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 2 2 votes Square on both sides $(\sqrt{5x+9} + \sqrt{5x-9})^{2} = 9(2+\sqrt2)^2$ . After opening the square and adding/subtracting some terms we will get $5x + \sqrt{(5x)^2 - 9^2} = 27 + 18\sqrt{2}$. Compare $ 5x$ with $27$ and $\sqrt{(5x)^2-9^2}$ with $18\sqrt2$ we will get $x=5.4$ putting the value into the equation $\sqrt{10*5.4 +9}$ we are getting $\sqrt{63}$ which is equal to $3\sqrt7$ Hence option $A$ is the answer. rhl answered Jul 3, 2025 • selected Jul 4, 2025 by Arjun rhl 642 points comment Share Follow 0 reply Please log in or register to add a comment.