0 votes 0 votes The number of non-negative real roots of $2^x - x - 1 =0$ equals _______ $0$ $1$ $2$ $3$ Quantitative Aptitude cat2003-1 quantitative-aptitude algebra + – go_editor asked Feb 5, 2016 • edited Apr 2, 2022 by Lakshman Bhaiya go_editor 13.9k points 1.0k views answer comment Share See all 0 reply Please log in or register to add a comment.
1 votes 1 votes x=0 and x= 1 are the real root of the equation So answer is C.2 Arnab Bhadra answered Jun 12, 2017 Arnab Bhadra 46 points comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes $2^{x}$ = x+1 Taking log$\log _{2}$ on both side, we get x = $\log _{2}$(x+1) x = $\log _{2}x*\log _{2}1$ x = 0 I am not sure correct me I m wrong VishalBarkule answered Jun 11, 2017 VishalBarkule 194 points comment Share See all 0 reply Please log in or register to add a comment.