In a triangle $\mathrm{A B C, A B=A C}=8 \mathrm{cm}$. A circle drawn with $\mathrm{BC}$ as diameter passes through $\mathrm{A}$. Another circle drawn with center at $\mathrm{A}$ passes through $\mathrm{B}$ and $\mathrm{C}$. Then the area, in $\mathrm{sq. cm}$, of the overlapping region between the two circles is
- $16(\pi-1)$
- $32 \pi$
- $32(\pi-1)$
- $16 \pi$