1 1 vote In a triangle $\mathrm{A B C, A B=A C}=8 \mathrm{cm}$. A circle drawn with $\mathrm{BC}$ as diameter passes through $\mathrm{A}$. Another circle drawn with center at $\mathrm{A}$ passes through $\mathrm{B}$ and $\mathrm{C}$. Then the area, in $\mathrm{sq. cm}$, of the overlapping region between the two circles is $16(\pi-1)$ $32 \pi$ $32(\pi-1)$ $16 \pi$ Quantitative Aptitude cat2022-set3 + – admin 5.3k points 1.1k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.