1 1 vote All the vertices of a rectangle lie on a circle of radius $R$. If the perimeter of the rectangle is $P$, then the area of the rectangle is $\frac{P^{2}}{16}-R^{2}$ $\frac{P^{2}}{8}-2 R^{2} $ $\frac{P^{2}}{2}-2 P R $ $\frac{P^{2}}{8}-\frac{R^{2}}{2}$ Quantitative Aptitude cat2022-set1 quantitative-aptitude + – admin 5.3k points 1.4k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.