Morning: Content = $C + k$
Afternoon: Keeps $\frac{4}{5}$ of total
$$C_n = \frac{4}{5}(C + k)$$
End of day content is 20% more than previous day
$$C_n = 1.2C$$
So:
$$\frac{4}{5}(C + k) = 1.2C$$
$$C + k = 1.5C$$
$$k = 0.5C$$
So new content = $0.5C$ = 50% of previous day's content