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Given that; $\frac{100x}{2x^2+102x+2}$

Taking $2x$ as common from the denominator we get;

$\implies \frac{100x}{2x(x+51+1/x)}$

$\implies \frac{50}{99+51}=1/3$ [$\because x+\frac{1}{x}=99$]

Option (A) is correct.

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