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lets assume that $A,B$ incomes are $4x,7x$ and their expenditures are in the ratio of $6y,11y$

Note: saving =total income-expenditure

now according to the given information:

$4x-6y=\frac{4x}{3}$

$\implies 4x=9y \implies x=\frac{9y}{4}$

so required saving ratio=$\frac{4x-6y}{7x-11y}$

put x value in given ratio we get:

$\implies \frac{\frac{36y}{4}-6y}{\frac{63y}{4}-11y}$

$\implies \frac{3y}{19y/4}=\frac{12}{19}=12:19$

Option (A) is correct.

Note: saving =total income-expenditure

now according to the given information:

$4x-6y=\frac{4x}{3}$

$\implies 4x=9y \implies x=\frac{9y}{4}$

so required saving ratio=$\frac{4x-6y}{7x-11y}$

put x value in given ratio we get:

$\implies \frac{\frac{36y}{4}-6y}{\frac{63y}{4}-11y}$

$\implies \frac{3y}{19y/4}=\frac{12}{19}=12:19$

Option (A) is correct.