# NIELIT 2022 Feb Scientist D - Section D: 13

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If $(0.0256) \div 0.064 \times (0.4)^{8} = (0.4)^{x} \times 0.16,$ the value of $x$ is :

1. $5$
2. $6$
3. $7$
4. $4$

Givne that : $0.0256\div 0.064\times(0.4)^8=(0.4)^x\times0.16$

$\implies 0.4\times (0.4)^8=(0.4)^x\times (0.4)^2$

$\implies (0.4)^9=(0.4)^x+2$

$\implies 9=x+2\implies x=7$

Option (C) is correct.

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