NIELIT 2022 Feb Scientist C - Section D: 30

Question

If $\dfrac{1}{5}$ of $645 + 7\dfrac{1}{3}$ of $33 – 3\dfrac{3}{4}$ of $x + 109 = 0$ then $x = \; :$

• A. $124$
• B. $120$
• C. $114$
• D. None of these

Answer 1

Given:$\frac{1}{5}\times 645+\frac{22}{3}\times 33-\frac{15x}{4}+109=0$

$\implies 129+242-\frac{15x}{4}+109=0$

$\implies-\frac{15x}{4}=-480$

$\implies x=\frac{480\times 4}{15}=128 $

Option (D) is correct.