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NIELIT 2019 Feb Scientist D - Section C: 11

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Best answer
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Rate reduce from $13\%$ to $12\frac{1}{2}\% $ p.a.

Decrease in rate $= 0.5\%$

Decline in interest $= \text₹~104$

$\begin{align} 0.5\%~of~capital &= 104 \\ \implies capital &= \frac{104}{0.5}\times 100 = \text₹~20800 \end{align}$

Option B.

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Answer is B

$\frac{P*13*1}{100}-\frac{P*25*1}{2*100} = 104$

P = 200*104 = Rs.20800

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