0 votes 0 votes $A$ and $B$ can complete a task in $30$ days when working together. After $A$ and $B$ have been working together for $11$ days, $B$ is called away and $A$, himself completes the task in the next $28$ days. Had $A$ been working alone, the number of days taken by him to complete the task would have been: $\dfrac{379}{9} \\$ $\dfrac{840}{19} \\$ $\dfrac{520}{11} \\$ $\dfrac{590}{11}$ Quantitative Aptitude nielit2019feb-scientistc work-time + – Lakshman Bhaiya asked Apr 1, 2020 • edited May 17, 2020 by go_editor Lakshman Bhaiya 13.8k points 662 views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Answer is B $A+B = \frac{1}{30}$ 11 days (A+B) work together + 28 days A alone worked = 1 11*$\frac{1}{30}$ + 28 * A = 1 On solving, we will get A’s 1 day work is $\frac{19}{840}$ No: of days taken by A to complete the work alone is $\frac{840}{19}$ neethu_seb answered Dec 14, 2022 neethu_seb 3.4k points comment Share See all 0 reply Please log in or register to add a comment.