NIELIT 2016 DEC Scientist B - Section A: 42

Question

A train started from Mumbai at $6.00$ A.M. On the next (second) station $1/3$ passengers got down and $96$ got in. On the next (third) station, $1/2$ of the total passengers present in the train, got down and $12$ came in. Now there were $248$ passengers in the train, when the train started from Mumbai, the number of passengers was:

• A. $435$
• B. $564$
• C. $654$
• D. $736$

Answer 1

Let the number of passenger in train(when train started from mumbai) $ = x$

From second station: The number of passenager $ = x – \dfrac{x}{3} + 96 = \dfrac{2x + 288}{3}$

From second station: The number of passenager $ = \dfrac{2x + 288}{3} – \left(\dfrac{ \dfrac{2x + 288}{3} }{2}\right) + 12$

Now,  $\dfrac{2x + 288}{3} – \left(\dfrac{ \dfrac{2x + 288}{3} }{2}\right) + 12 = 248$

$\implies \dfrac{2x + 288}{3} – \left(\dfrac{x + 144}{3}\right) + 12 = 248$

$\implies \dfrac{2x + 288 – x – 144 + 36}{3} = 248$

$\implies x + 180 = 744$

$\implies x = 564.$

So, the correct answer is $(B).$