Given that,
$ 0.25 < 2^{x} < 200 $
$ \Rightarrow \frac {25}{100} < 2^{x} < 200 $
$ \Rightarrow \frac {1}{4} < 2^{x} < 200 $
$ \Rightarrow 2^{-2} < 2^{x} < 200 \quad \longrightarrow (1)$
From equation $(1)$
$ 2^{-2} < 2^{x}$
$ \Rightarrow 2^{x} > 2^{-2}$
$ \Rightarrow \boxed{x > -2}$
And, $ 2^{x} < 200 $
We know, that $ 2^{8} = 256,$ so here $ x $ should be less than $8. \Rightarrow \boxed {x < 8}$
Now, we have $ \boxed { -2 < x < 8}$
Therefore, possible value of $ x: \{ -1,0,1,2,3,4,5,6,7\}$
$ 2^{x} + 2 $ is perfectly divisible by either $3$ or $4:$
Now, we can put the values of $x$ and see, which one is satisfied.
- $ x = -1 \Rightarrow 2^{-1} + 2 = \frac{1}{2} + 2 = \frac{5}{2} \; ($It is not divisible by either $3$ or $4)$
- $ x = 0 \Rightarrow 2^{0} + 2 = 1 + 2 = 3\;($It is divisible by $3)$
- $ x = 1 \Rightarrow 2^{1} + 2 = 4\;($It is divisible by $4)$
- $ x = 2 \Rightarrow 2^{2} + 2 = 6\;($It is divisible by $3)$
- $ x = 3 \Rightarrow 2^{3} + 2 = 10 \;($It is not divisible by either $3$ or $4)$
- $ x = 4 \Rightarrow 2^{4} + 2 = 18\;($It is divisible by $3)$
- $ x = 5 \Rightarrow 2^{5} + 2 = 34 \;($It is not divisible by either $3$ or $4)$
- $ x = 6 \Rightarrow 2^{6} + 2 = 66 \;($It is divisible by $3)$
- $ x = 7 \Rightarrow 2^{7} + 2 = 130 \;($It is not divisible by either $3$ or $4)$
$ \therefore $ The number of integers $x = \{0,1,2,4,6\}$
Correct Answer $: 5 $