1 1 vote The points $\left ( 2,5 \right )$ and $\left ( 6,3 \right )$ are two end points of a diagonal of a rectangle. If the other diagonal has the equation $y=3x+c$, then $c$ is $-5$ $-6$ $-7$ $-8$ Quantitative Aptitude cat2017-2 quantitative-aptitude cartesian-coordinates + – go_editor 14.2k points 1.8k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote We can draw the diagram for better understanding. Let the midpoint of the rectangle be $M(x,y)$. In a rectangle, diagonals bisect each other. So, one diagonal should pass through the midpoint of the other. Midpoint $M(x,y)=M\left(\frac{2+6}{2},\frac{5+3}{2}\right) = M\left(\frac{8}{2},\frac{8}{2}\right) = M(4,4)$ The other diagonal, $y=3x+c$ should also pass through $(4,4):$ Now, $4 = 3(4) + c$ $\Rightarrow c = 4-12$ $\Rightarrow \boxed{c = -8}$ $\therefore$ The value of $c$ is $ -8.$ Correct Answer $:\text{D}$ Anjana5051 answered Dec 31, 2021 • edited Jan 19, 2022 by Lakshman Bhaiya Anjana5051 12.1k points comment Share Follow 0 reply Please log in or register to add a comment.