0 0 votes In the figure below, $\angle \text{MON} = \angle \text{MPO} = \angle \text{NQO} = 90^{\circ}$ and $\text{OQ}$ is the bisector of $\angle \text{MON}$ and $\text{QN} = 10, \text{OR} = 40/7$. Find $\text{OP}$. $4.8$ $4.5$ $4$ $5$ Quantitative Aptitude cat2012 quantitative-aptitude geometry + – Chandanachandu 344 points 1.3k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.