0 votes 0 votes In how many ways 8 persons can be arranged on two round tables consisting of 4 chairs each? a)720 b)1260 c)2520 d)5040 Quantitative Aptitude quantitative-aptitude permutation-combination 1-mark + – Pooja Palod asked Sep 27, 2015 Pooja Palod 1.8k points 1.1k views answer comment Share See all 3 Comments See all 3 3 Comments reply Abhigolu_1 10 points commented 1 day ago reply Share can anyone explain this pls. In the solution given below why aren't we multiplying it by 2 for selecting on which table which group is going?? My answer was coming 5040 becoz of that table selction. 0 votes 0 votes Arjun 8.6k points commented 1 day ago reply Share There are two tables. Let them be A and B. We are selecting 4 people for A. Then 4 people for B. If we first select 4 people for B, this case will already be part of the above selection as any 4 people out of 8 can go to A or B. This way order in which we fill tables A or B doesn't matter for the total possibilities. 1 votes 1 votes Abhigolu_1 10 points commented 1 day ago reply Share ok sir thanks samjh gaya mai 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes Answer should be 8C4x((4 - 1)!)^2 = 2520. All possible ways of making two groups of 4 people out of 8 people = 8C4. IN EACH ROUND TABLE, all possible ways of arranging 4 people = (4 - 1)! Which gives 8C4x((4 - 1)!)^2 = 2520. अनुराग पाण्डेय answered Sep 27, 2015 अनुराग पाण्डेय 1.4k points comment Share See all 0 reply Please log in or register to add a comment.