2 votes 2 votes Quantitative Aptitude profit-loss quantitative-aptitude + – Mk Utkarsh asked Dec 3, 2017 Mk Utkarsh 256 points 5.0k views answer comment Share See all 0 reply Please log in or register to add a comment.
Best answer 1 votes 1 votes Cost Price of Computers are 20000(the one on which he has profit) and 30000 (loss) Total cost price=50000 Total selling price = 48000 $\therefore$ Loss percent = 4 % saxena0612 answered Dec 3, 2017 • selected Dec 3, 2017 by Mk Utkarsh saxena0612 950 points comment Share See all 0 reply Please log in or register to add a comment.
1 votes 1 votes Simple formula, if an item is sold at same price in both cases, and if there is x% loss in one case, while x% profit in the other, than overall, there is LOSS. And, Loss% = (x/10)^2. Therefore, here there is LOSS, and Loss% = (20/10)^2 = 4% Naman9495 answered Dec 12, 2020 Naman9495 62 points comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes sp1 = 24000 for the first comp. he gained 20% profit which is equal to 1/5 cp1 : sp1 denominator: denominator+nominator 5 : 6 5*4000=20000:6*4000=24000 sp2 = 24000 for the first comp. he loss 20% which is equal to 1/5 cp2 : sp2 denominator: denominator-nominator 5 : 4 5*6000=30000:4*6000=24000 total cost price cp = cp1+cp2 = 20000+30000 = 50000 total selling price sp = sp1+sp2 = 24000+24000 = 48000 total loss = 50000-48000 = 2000 hence cp : sp 50000:48000 25:24 1/25*100 = 4% he got loss of 4% answer. bhupendrakumar answered Sep 12, 2019 bhupendrakumar 18 points comment Share See all 0 reply Please log in or register to add a comment.