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In the given figure, $EADF$ is a rectangle and $ABC$ is a triangle whose vertices lie on the sides of $EADF$. $AE = 22,BE = 6,CF = l6$ and $BF = 2$. Find the length of the line joining the midpoints of the sides $AB$ and $BC$.

  1. $4\sqrt{2}$
  2. $5$ 
  3. $3.5$ 
  4. None of these
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EF = EB + BF = 6 + 2 = 8

CD = AE - CF = 22 - 16 = 6

BC2 = BF2 + FC2

=> BC = $\sqrt{260}$

Similarly, AB = $\sqrt{520}$

And AC = 10

By the property of similar triangle, the length of the line joining the midpoints of the sides AB and BC is 5 (Option B)

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