0 0 votes AB is the diameter of the given circle, while points C and D lie on the circumference as shown. If AB is $15$ cm, AC is $12$ cm and BD is $9$ cm, find the area of the quadrilateral ACBD. $54 \pi$ $216\pi$ $162\pi$ None of these Quantitative Aptitude cat1997 quantitative-aptitude + – Misbah Ghaya 8.9k points 1.9k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes Angle C and D will be right angles BC will be 9 cm (Applying Pythagoras theorem) AD will be 12 cm (Applying Pythagoras theorem) Area of the quadrilateral = Area of triangle ABC + Area of triangle ABD = 54 + 54 = 108 cm square mudit23june answered Jun 28, 2017 mudit23june 348 points comment Share Follow 0 reply Please log in or register to add a comment.