0 0 votes In a circle with center $\operatorname{C}$ and radius $6 \sqrt{2} \mathrm{~cm}, P Q$ and $S R$ are two parallel chords separated by one of the diameters. If $\angle P Q C=45^{\circ}$, and the ratio of the perpendicular distance of $P Q$ and $S R$ from $\operatorname{C}$ is $3: 2$, then the area, in sq. cm , of the quadrilateral $P Q R S$ is$4(3+\sqrt{14})$$4(3 \sqrt{2}+\sqrt{7})$$20(3+\sqrt{14})$$20(3 \sqrt{2}+\sqrt{7})$ Others cat2025-set1 + – Shubham Sharma 2 4.7k points 127 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.