2 2 votes Two people are selected at random from a group, assuming that:Each day of the year is equally likely to be a birthday.There are 365 days in a year (ignoring leap years).Birthdays of different people are independent events.What is the probability that both selected people share the same birthday?Please provide a clear explanation of the reasoning process or formula used. Quantitative Aptitude quantitative-aptitude probability + – kangsheng 44 points 12.9k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
2 2 votes 0.27 Pratyush_Mehta answered Dec 14, 2025 Pratyush_Mehta 62 points comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes The chance that two randomly selected people share the same birthday (ignoring leap years) is:1 / 365, which is about 0.27%.This is because once one person’s birthday is fixed, the second person has a 1-in-365 chance of having the same birthday. Jameswood answered Jan 13 Jameswood 66 points comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes The chance that two randomly selected people share the same birthday is about 1 in 365 (0.27%). Sofiajackson answered Jan 19 Sofiajackson 22 points comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Person 1: Can have birthday on ANY day → $\frac{365}{365} = 1$Person 2: Must match Person 1's birthday → $\frac{1}{365}$Probability both share same birthday:$$P = 1 \times \frac{1}{365} = \frac{1}{365}$$Answer: $\frac{1}{365}$ Gopika_G answered Mar 29 Gopika_G 84 points comment Share Follow 0 reply Please log in or register to add a comment.