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CAT 2000 | Question: 95

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Given,


x$^2$+y$^2$=0.1

|x–y|=0.2

x$^2$+y$^2$=0.1= (x-y)$^2$-2xy

0.1= 0.04-2xy

-2xy=0.06

xy= – 0.03

Checking the options, |x| and |y| can be 0.1 and 0.3 respectively which adds up to 0.4
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