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CAT 2000 | Question: 61

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Consider a sequence of seven consecutive integers. The average of the first five integers is $n.$ The average of all the seven integers is

  1. $n$
  2. $n+1$
  3. $\text{K} \times n, \text {where K is a function of } n$
  4. $n + \frac{2}{7}$

1 Answer

1 1 vote

 

 
 
Consider this sequence of seven consecutive integers:  a, a+1, a+2, a+3, a+4, a+5, a+6
 
The average of first 5 integers is n, i.e
(2a+4)/2 = n
2a+4=2n
a+2=n    - i
 
The average of all 7 integers is:
(2a+6)/2=x
2a+6=2x
a+3=x    - ii
 
From i and ii:
a+3 = x = n+1
 

Thus, the average of all the seven integers is B. n+1

 
 
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