0 0 votes If $f(x) = \log(1+x)/(1-x))$, then $f(x)+f(y)=$ $f(x+y)$ $f(1+xy)$ $(x+y) \: f(1+xy)$ $f (\frac{x+y}{1+xy})$ Quantitative Aptitude cat2002 quantitative-aptitude functions + – go_editor 14.2k points 939 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.