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Pipes $\mathrm{A}$ and $\mathrm{C}$ are fill pipes while Pipe $\mathrm{B}$ is a drain pipe of a tank. Pipe $\mathrm{B}$ empties the full tank in one hour less than the time taken by Pipe $\mathrm{A}$ to fill the empty tank. When pipes $\mathrm{A, B}$ and $\mathrm{C}$ are turned on together, the empty tank is filled in two hours. If pipes $\mathrm{B}$ and $\mathrm{C}$ are turned on together when the tank is empty and Pipe $\mathrm{B}$ is turned off after one hour, then Pipe $\mathrm{C}$ takes another one hour and $15$ minutes to fill the remaining tank. If Pipe $\mathrm{A}$ can fill the empty tank in less than five hours, then the time taken, in minutes, by Pipe $\mathrm{C}$ to fill the empty tank is

  1. $75$
  2. $120$
  3. $60$
  4. $90$

     

1 Answer

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We can use the help of fractions contributed per pipe to solve this problem


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