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For any natural number $n$, suppose the sum of the first $n$ terms of an arithmetic progression is $\left(n+2 n^{2}\right)$. If the $n^{\text {th }}$ term of the progression is divisible by $9$ , then the smallest possible value of $n$ is

  1. $8$
  2. $7$
  3. $4$
  4. $9$
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