0 votes 0 votes If $x + \dfrac{1}{x} = 99,$ then the value of $\dfrac{100x}{2x^{2} + 102x + 2}$ is : $1/3$ $1/99$ $99/100$ $3$ Quantitative Aptitude nielit2022feb-scientistd + – Lakshman Bhaiya asked Jul 22, 2022 • edited Aug 27, 2022 by Lakshman Bhaiya Lakshman Bhaiya 13.7k points 378 views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Given that; $\frac{100x}{2x^2+102x+2}$ Taking $2x$ as common from the denominator we get; $\implies \frac{100x}{2x(x+51+1/x)}$ $\implies \frac{50}{99+51}=1/3$ [$\because x+\frac{1}{x}=99$] Option (A) is correct. Hira Thakur answered Sep 4, 2022 Hira Thakur 7.1k points comment Share See all 0 reply Please log in or register to add a comment.