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Let’s assume that number is $x$

it is given that $x>44^2=1936$ and $x<45^2=2025$

it is also given that the factor is $6^2=36$ and the number is multiple of 5.

we can find $LCM(36,5)=180$

therefore our number should be multiple of $180$

Only option $(B)$ satisfied the condition.

Option $(B)$ is correct.

it is given that $x>44^2=1936$ and $x<45^2=2025$

it is also given that the factor is $6^2=36$ and the number is multiple of 5.

we can find $LCM(36,5)=180$

therefore our number should be multiple of $180$

Only option $(B)$ satisfied the condition.

Option $(B)$ is correct.