Register

NIELIT 2019 Feb Scientist D - Section C: 10

• retagged by
816 views
0 votes
0 votes

If $9$ men working $7\frac{1}{2}$ hours a day can finish a work in $20$ days, then how many days will be taken by $12$ men working $6$ hours a day to finish the work, it being given that $3$ men of former type work as much as $2$ men of the latter type in the same time ?

  1. $12\frac{1}{2}$
  2. $13$
  3. $9\frac{1}{2}$
  4. $11$
• retagged by
User Avatar

1 Answer

Best answer
3 votes
3 votes

$9$ men working $7\frac{1}{2}$ hours a day can finish a work in $20$ days,

Total men hours required $=9\times \frac{15}{2} \times 20 = 9\times15 \times 10$ hours.

$3$ men of former type work as much as $2$ men of the latter type,

$\therefore$ Total men hours required for latter type = $\frac{2}{3}$ of total men hours for the former type

Let they require $x$ days to finish the work,

$\require{cancel}  \begin{align} 12\times 6\times x &= \frac{2}{\cancel3} \times \cancelto{3}{9}\times 15\times 10 \\ \implies x &=\frac{ \cancel2 \times \cancel3 \times \cancelto{5}{15} \times \cancelto{5}{10}}{\cancelto{2}{12}\times \cancel6} \\ \implies x &= \frac{25}{2} = 12\frac{1}{2} \end{align} $

Option A is correct.

• selected by
User Avatar
Voting & Accepting an answer helps improve the community
← PreviousNext →
← Previous in categoryNext in category →
Answer:

Related questions

0 votes
0 votes
1 answer
1
Lakshman Bhaiya asked Apr 3, 2020
550 views
NIELIT 2019 Feb Scientist D - Section C: 8
$A$ can do a piece of work in $14$ days which $B$ can do in $21$ days. They begin together but $3$ days before the completion of the work, $A$ leaves off. The total number of days to complete the work is : $\frac{33}{5}$ $8\frac{1}{2}$ $\frac{51}{5}$ $13\frac{1}{2}$
$A$ can do a piece of work in $14$ days which $B$ can do in $21$ days. They begin together but $3$ days before the completion of the work, $A$ leaves off. The total numbe...
2 votes
2 votes
1 answer
2
Lakshman Bhaiya asked Apr 3, 2020
624 views
NIELIT 2019 Feb Scientist D - Section D: 10
In an acute angled triangle $ABC$, if $\tan \left(A+B-C \right)=1$ and $\sec \left(B+C-A \right)=2$, Find angle $A$. $60^\circ$ $45^\circ$ $30^\circ$ $90^\circ$
In an acute angled triangle $ABC$, if $\tan \left(A+B-C \right)=1$ and $\sec \left(B+C-A \right)=2$, Find angle $A$.$60^\circ$$45^\circ$$30^\circ$$90^\circ$
0 votes
0 votes
1 answer
3
Lakshman Bhaiya asked Apr 3, 2020
642 views
NIELIT 2019 Feb Scientist D - Section C: 1
The $L.C.M$ of $\left (x^{3}-x^{2}-2x \right)$ and $\left (x^{3}+x^{2} \right)$ is : $\left (x^{3}-x^{2}-2x \right)$ $\left (x^{2}+x \right)$ $\left (x^{4}-x^{3}-2x^{2} \right)$ $x-2$
The $L.C.M$ of $\left (x^{3}-x^{2}-2x \right)$ and $\left (x^{3}+x^{2} \right)$ is : $\left (x^{3}-x^{2}-2x \right)$$\left (x^{2}+x \right)$$\left (x^{4}-x^{3}-2x^{2} \ri...
0 votes
0 votes
1 answer
4
Lakshman Bhaiya asked Apr 3, 2020
803 views
NIELIT 2019 Feb Scientist D - Section C: 2
Ashok's age is $\left (\frac{1}{6} \right)^{th}$ of his father's age. The father's age will be twice of Kamal's age after $10$ years. If Kamal's eighth birthday was celebrated $2$ years before, what is Ashok's present age ? $24$ years $30$ years $\frac{20}{3}$ years None
Ashok's age is $\left (\frac{1}{6} \right)^{th}$ of his father's age. The father's age will be twice of Kamal's age after $10$ years. If Kamal's eighth birthday was celeb...
1 votes
1 votes
1 answer
5
Lakshman Bhaiya asked Apr 3, 2020
654 views
NIELIT 2019 Feb Scientist D - Section C: 3
If $t^{2}-4t+1=0$, then the value of $\left[t^{3}+1/t^{3} \right]$ is : $44$ $48$ $52$ $64$
If $t^{2}-4t+1=0$, then the value of $\left[t^{3}+1/t^{3} \right]$ is :$44$$48$$52$$64$
Link Copied!