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NIELIT 2019 Feb Scientist D - Section C: 13

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Ans is option (C)

In the figure, the man’s height i.e. length of segment $DE=1.4m$

Length of the man’s shadow i.e. length of segment $EC=1.2m$

Height of the tower i.e. length of segment $AB=h$ mtr

Length of tower’s shadow i.e. length of segment $BC=5.4m$

$\therefore$  $tanC=\frac{DE}{EC}=\frac{AB}{BC}$

$\Rightarrow$   $\frac{1.4}{1.2}=\frac{h}{5.4}$

$\Rightarrow$   $h=6.3m$

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