0 votes 0 votes The value of $\large\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$ is : $0.86$ $0.95$ $0.97$ $1.06$ Quantitative Aptitude nielit2016mar-scientistc algebra + – Lakshman Bhaiya asked Apr 2, 2020 • edited Oct 31, 2020 by soujanyareddy13 Lakshman Bhaiya 13.7k points 1.0k views answer comment Share See all 0 reply Please log in or register to add a comment.
0 votes 0 votes These type of questions are based on direct formulae of a^3 -b^3 and/or a^2 – b^2 etc. Here, $a^{3}-b^{3} =(a-b)(a ^{2}+ b ^{2} +ab)$ So Simply, from question, a= 0.96 and b=0.10 So, Answer is 0.86 Devwritt answered Nov 19, 2020 Devwritt 344 points comment Share See all 0 reply Please log in or register to add a comment.