NIELIT 2016 DEC Scientist B - Section A: 50

Question

$A$ can run $200$ m in $35$ seconds and $B$ in $38$ seconds. By what distance $A$ beats $B$?

• A. $15$ m
• B. $15\dfrac{2}{3}$ m
• C. $15\dfrac{15}{19}$ m
• D. $15\dfrac{4}{19}$ m

Answer 1

$A$ can run $200\;m$ in $35\; sec,$ so in $1\;sec\; A$ can run $\dfrac{200}{35}\;m = \dfrac{40}{7}\;m = 5.71\;m$

And, $B$ can run $200\;m$ in $38\;sec,$ so in $1\;sec\; B$ can run $\dfrac{200}{38}\;m = \dfrac{100}{19}\;m = 5.26\;m$

Now, $B$ run $35\;sec$ then distance cover by $B = 5.26\;m \times 35 = 184.1\:m$

$\therefore\;A$ can beat $B$ by $200 – 184.1 = 15.9\:m \approx 15\dfrac{15}{19}\;m.$

So, the correct answer is $(C).$