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On throwing two dices  Possible Outcomes are:

  • $(1,1),(1,2),(1,3),{\color{Red}{(1,4)}},(1,5),(1,6)$
  • $(2,1),(2,2),{\color{Red} {(2,3)}},(2,4),(2,5),(2,6)$
  • $(3,1),{\color{Red}{(3,2)} },(3,3),(3,4),(3,5),(3,6)$
  • ${\color{Red}{(4,1)}},(4,2),(4,3),(4,4),(4,5),(4,6)$
  • $(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)$
  • $(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)$

 $P(\text{sum as}\; 5) = \dfrac{4}{36} = \dfrac{1}{9}$

$\textrm{Option C,}$

Answer:

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