edited by
687 views
1 votes
1 votes

Mukesh purchased $10$ bicycles in $2017$, all at the same price. He sold six of these at a profit of $25\%$ and the remaining four at a loss of $25\%$. If he made a total profit of Rs.$2000$, then his purchase price of a bicycle, in Rupees, was  ________

  1. $8000$
  2. $6000$
  3. $4000$
  4. $2000$
edited by

1 Answer

1 votes
1 votes

Given that, Mukesh purchased $10$ bicycles in $2017$, all at the same price.

Let $x$ be the purchase price (cost price) of one bicycle.

Then, the price of $10$ bicycles is $10x.$

He sold six bicycles at a profit of $25\% .$

  • Selling price of $6$ bicycles $=6x \times \frac {125}{100}= \frac {15x}{2}$

He sold the remaining $4$ bicycles at a loss of $25\%$

  • Selling price of $4$ bicycles $= 4x \times \frac {75}{100}=3x$

Total selling price of $10$ bicycles $= \frac {15x}{2} + 3x= \frac {15x+6x}{2}= \frac {21x}{2}$

$ \boxed {\text {profit =  selling  price –  cost  price} }$

$2000= \frac{21x}{2} – 10x$

$ \Rightarrow 2000 = \frac {21x-20x}{2}$

$ \Rightarrow 2000 = \frac {x}{2}$

$ \Rightarrow x= 4000 $

$\therefore$ Mukesh purchased a bicycle in Rs. $4000$

Correct Answer: C

edited by
Answer:

Related questions

1 votes
1 votes
1 answer
2
1 votes
1 votes
1 answer
3
go_editor asked Mar 20, 2020
480 views
If x is a real number, then $\sqrt{\log _{e}\frac{4x-x^{2}}{3}}$ is a real number if and only if$1\leq x\leq 2$$-3\leq x\leq 3$$1\leq x\leq 3$$-1\leq x\leq 3$
1 votes
1 votes
1 answer
4
1 votes
1 votes
1 answer
5
go_editor asked Mar 20, 2020
632 views
How many pairs $(m,n)$ of positive integers satisfy the equation $m^{2}+105=n^{2}$ _______