$\text{ABCD}$ is a rectangle. The points $\text{P}$ and $\text{Q}$ lie on $\text{AD}$ and $\text{AB}$ respectively. If the triangle $\text{PAQ, QBC}$ and $\text{PCD}$ all have the same areas and $\text{BQ} = 2$, then $\text{AQ} = $
- $1+\sqrt{5}$
- $1-\sqrt{5}$
- $\sqrt{7}$
- $2\sqrt{7}$